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Question

A string of length 2 m is fixed at both ends. If this string vibrates in its fourth normal mode with a frequency of 500 It's then the waves would travel on it with a velocity of:

A
125 m/s
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B
250 m/s
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C
500 m/s
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D
1000 m/s
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Solution

The correct option is C 500 m/s
(c) For string λ=2lp
where p= No. of loops = Order of vibrationHence for forth mode p=4λ=l2
Hence v=nλ=500×22=500 m/s

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