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Question

A string of length 36cm was in unison with a fork of frequency 256Hz. It was in unison with another fork when the vibrating length was 48cm, the tension being unaltered. The frequency of second fork is

A
212Hz
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B
320Hz
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C
384Hz
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D
192Hz
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Solution

The correct option is D 192Hz
f=v2L
v=f(2 L)
=256×2×36
=18432 cm/s.

wave velocty remains same
f=v2L
=184322×48
=192 Hz.

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