A string of length 36cm was in unison with a fork of frequency 256Hz. It was in unison with another fork when the vibrating length was 48cm, the tension being unaltered. The frequency of second fork is
A
212Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
320Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
384Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
192Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D192Hz f=v2L v=f(2L) =256×2×36 =18432cm/s.
wave velocty remains same f=v2L =184322×48 =192Hz.