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Question

A string of lengthLfixed at both ends vibrates in its fundamental mode at a frequency v, and maximum amplitude A.

a Find the wavelength and the wave numberk.

b Take the origin at one end of the string and the X-axis along the string. Take the Y-axis along the direction of the displacement. Taket=0 at the instant when the middle point of the string passes through its mean position and is going in the positive y-direction. Write the equation describing the standing wave.


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Solution

Step 1: Given data

Length of the string=L

Frequency of vibration=v

Maximum amplitude of vibrations=A

Step 2: Find wavelength of the wave

Velocity of wave, V=(Tm)

wavelength, λ=Velocity/Frequency

=(Tm)[(12L)(Tm)] [As, frequency=(12L)×V]

=2L

Hence, wavelength is 2L.

Step 3: Find wavenumber of the wave

wave number, k=2πλ

k=2π2Lk=πL

Hence, the wavenumber of the wave is πL

Step 4: Write equation for the stationary wave

Equation of the stationary wave, y=Acos(2πxλ)sin(2πVtλ)

As, frequency of vibration

v=Vλv=V2L

y=Acos(2πxλ)sin(2πvtλ)y=Acos(2πx2L)sin(2πvt2L)y=Acos(πxL)sin(πvtL)

Equation for the stationary wave,

y=Acos(πxL)sin(πvtL)

Hence, wavelength is 2L.

Hence, the wavenumber of the wave is πL.

Hence, equation for the stationary wave is y=Acos(πxL)sin(πvtL).


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