A string of length L and force constant K is stretched to obtain extension l. It is further stretched to obtain extension l1. The work done in second stretching is:
A
12Kl1(2l+l1)
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B
12Kl21
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C
12K(l2+l21)
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D
12K(l21−l2)
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Solution
The correct option is D12K(l21−l2) Work done in stretching =U2−U1 U(Potential energy)=12kx2 ∴ x = extension from natural length U2=12×kl21 U1=12×kl2 Work done =k2[l21−l2]