A string of length L and mass M hangs freely from a fixed point. Then, the velocity of transverse waves along the string at a distance x from the free end is
A
gx
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
√gx
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
gL
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
√gL
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B√gx Total length of string =L Mass of the string =M The velocity of transverse wave v=√Tm where, T= weight of part of string hanging below the point under consideration =(ML)xg ⇒v=
⎷(ML)xg(ML)=√xg