A string of length l fixed at both ends vibrates in resonance with a tuning fork of frequency 'f' at two successive values of tension T1 and T2 in the string. Find the specific mass (mass per unit length) of the string.
A
4T1T2f2l2(√T1+√T2)2
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B
T1T24f2l2(√T1−√T2)2
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C
4T1T2f2l2(√T1−√T2)2
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D
2T1T2f2l2(√T1+√T2)2
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Solution
The correct option is BT1T24f2l2(√T1−√T2)2 f=n2l√T1μ.....(1)f=n+12l√T2μ...(2) from equations (1) and (2) eliminate 'n' to get μ μ=T1T24f2l2(√T1−√T2)2