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Standard XII

Physics

Wave Speed expression

A string of l...

Question

A string of linear density $0.2 k g$ per metre is stretched with a force of $500 N$ . A transverse wave of length $4.0$ metre and amplitude $(1 / π)$ metre is travelling along it. Then the speed of the wave is

50 m / s

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12.5 m / s

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62.5 m / s

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2500 m / s

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Solution

The correct option is A $50 m / s$
given Tension $T = 500 N$ and mass per unit length $μ = 0.2 k g / m$
we get speed of wave $v = \sqrt[2]{T / m} = \sqrt[2]{\frac{500}{0.2}} = 50 m / s$
Option A is correct.

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A string of linear density 0.2kg per metre is stretched with a force of 500N. A transverse wave of length 4.0 metre and amplitude (1/π) metre is travelling along it. Then the speed of the wave is

The correct option is A 50m/sgiven Tension T=500N and mass per unit length μ=0.2kg/mwe get speed of wave v=2√T/m=2√5000.2=50m/s Option A is correct.

A string of linear density $0.2 k g$ per metre is stretched with a force of $500 N$ . A transverse wave of length $4.0$ metre and amplitude $(1 / π)$ metre is travelling along it. Then the speed of the wave is

The correct option is A $50 m / s$
given Tension $T = 500 N$ and mass per unit length $μ = 0.2 k g / m$
we get speed of wave $v = \sqrt[2]{T / m} = \sqrt[2]{\frac{500}{0.2}} = 50 m / s$
Option A is correct.