The correct option is
A l
At instant in between of a motion FBD will be as :
For pure rolling
$\vec {v} A=0$
⇒v−wR 0⇒V=wR
→vB=v+wR=2v
velocity of string unwrapping from the cylinder = vel of B w.r.t. center of mass
=→vB/0
→vB/0=2v−v=v
Distance traveled by the cylinder during its motion =∫t0v.dt=l
where t is time of motion
So,
Distance (length ) of the string passed through man's hand =∫t0→vB/0.dt
=∫t0v.dt=l
Option A is correct.