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Question

A string of negligible thickness is wrapped
several times around a cylinder kept on a rough horizontal surface. A man
standing at a distance l from the cylinder holds one end of the
string and pulls the cylinder towards him (figure 10-Q4). There is no slipping
anywhere. The length of the string passed through the hand of the man while the
cylinder reaches his hands is

1050091_50663bb16dd346eeab567919b2c3a973.PNG

A
l
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B
2l
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C
3l
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D
4l
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Solution

The correct option is A l
At instant in between of a motion FBD will be as :
For pure rolling
$\vec {v} A=0$
vwR 0V=wR
vB=v+wR=2v
velocity of string unwrapping from the cylinder = vel of B w.r.t. center of mass
=vB/0
vB/0=2vv=v
Distance traveled by the cylinder during its motion =t0v.dt=l
where t is time of motion
So,
Distance (length ) of the string passed through man's hand =t0vB/0.dt
=t0v.dt=l
Option A is correct.

1426855_1050091_ans_2ceed90179a64157a081f7a45feb48f6.png

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