Question

A strip footing of width 1.5 m is laid at a depth of 1 m. The ultimate bearing capacity of soil (in $kN/m^2$) is ?


For $\varphi ={30}^{\circ },(N_c=19,N_q=8.3,N_{\gamma }=5.7)$

• A. 403.5
• B. 416.3
• C. 424.8
• D. 432.6

Answer 1

The correct option is A 403.5



$q_u=C^{\prime }{N}_c+\gamma D_f{N}_q+0.5B\gamma N_{\gamma }{W}_{\gamma }$

$W_{\gamma }=0.5+0.5\frac{b}{B}=0.5+0.5\times \frac{1}{1.5}=0.833$

$q_u=(10\times 19)+(18\times 1\times 8.3)+(0.5\times 1.5\times 18\times 5.7\times 0.833)$

$=403.5kN/m^2$