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Question

a strong current of trivalent gaseous boron passes through a silicon crystal decreases the density of the crystal due to the part replacement of silicon by boron and due to the interstitial vacancies carried by the missing silicon atoms . in one such experiment one gram of silicon is taken and the boron atoms are found to be 1000pm by mass when the density of the silicon crystal decreases by 12%. the percentagesof missing vacancies due to silicon which are filled up by boron atoms is

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Solution

1 g Germanium------- 150 ppm = 1.5 * 10^-4 g Boron

4% decrease---- now weight is 0.96 g(Ge + B)----0.04 g missing

0.04 missing-------- (0.04-0.00015)g Ge missing------(0.04-0.00015)/72.61 moles
Ge missing=5.488*10^-4 moles

Boron replaced= 1.5*10^-4 g = (1.5*10^-4)/10 moles

equivalently replaced = 3/4((1.5*10^-4)/10) moles of Ge ( Valency of B is 3 and
Ge is 4)

= 0.1125*10^-4 moles of Ge

% of Missing vacancies filled by B atoms = 0.1125*100/5.488 = 2.05 %

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