Question

A strongly alkaline solution of a monoaminodicarboxylic acid contains how many basic groups ?

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

The correct option is C

3

In a strongly alkaline solution of an amino acid all of its - COOH groups are converted into $-CO{O}^{-}$. Thus a strongly alkaline solution of a monoaminodicarboxylic acid will have one $-N{H}_2$ and two $-CO{O}^{-}$groups, all of which are basic in nature. Further, remember that a $-N{H}_2$ is more basic than a $-CO{O}^{-}$ group