CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A student added 2 mL of 0.1 M CaCl2 to 2 mL of 0.1 M Na2CO3 in a test tube. He observed a white precipitate form.What was the identity of the precipitate?

A
CaCl2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Na2CO3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
NaCl
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
CaCO3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D CaCO3
Here CaCl2 react with Na2CO3 to give white ppt of CaCO3 and NaCl
CaCl2+Na2CO3CaCo3+2NaCl

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Werner's Coordination Theory
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon