wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A student appears for test 1,2 and 3. The student is successul if he passes either in tests 1 and 2 or tests 1 and 3. The probability of student passing in tests 1,2 and 3 is a,b,12 respectively.If the probability that the student is successful is 12. Then,


A

a=b=1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

a=b=1/2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

a=1 and b=0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

a=1 and b=1/2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

a=1 and b=0


P(PFP)+P(PPP)+P(PPF)=12

a×(1b)×12+ab2+ab2=12

a(1b)+2ab=1

a+ab=1

This is possible only when a=1 and b=0


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Defining Probability
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon