A student completed a genetics exercise by preparing this Punnett square. [Note: 'T' represents a dominant allele and 't' represents a recessive allele.]
What were the likely genotypes of the parents ?

Parent 1 was homozygous, parent 2 was heterozygous.

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Parent 1 was heterozygous, parent 2 was homozygous.

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Both parents were heterozygous.

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Both parents were homozygous.

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Solution

The correct option is C Both parents were heterozygous.
The “3 dominant: 1 recessive” phenotypic ratio or “1 homozygous dominant :2 heterozygous dominant: 1 homozygous recessive” genotypic ratio is obtained by self pollination of $F_{1}$ monohybrid. Thus, both parents are heterozygous tall (Tt). The presence of one homozygous parent would given the monohybrid test cross ratio of 1:1. Homozygous varieties produce uniform $F_{1}$ generation of dominant or recessive individuals depending upon the genotype of homozygous parent. Thus, the correct answer is option C.

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A student completed a genetics exercise by preparing this Punnett square. [Note: 'T' represents a dominant allele and 't' represents a recessive allele.]What were the likely genotypes of the parents ?

A student completed a genetics exercise by preparing this Punnett square. [Note: 'T' represents a dominant allele and 't' represents a recessive allele.]
What were the likely genotypes of the parents ?