wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A student constructed an electrochemical cell by using two electrodes: Zn/Zn​2+(1M) and Mg/Mg2+(1M) and represented it as Zn/Zn2+(1M)||Mg2+(1M)/Mg.
Is the representation correct? Justify. Given E0Mg2+/Mg=-2.37V;E0​Zn2+/Zn​=-0.76V

Open in App
Solution

The given cell is Zn/Zn2+(1M)||Mg2+(1M)/MgAs per the given cell the reaction isAnode : Zn Zn2+ + 2e-Cathode: Mg2+ + 2 e- MgSo Zinc undergoes oxidation and Mg undergoes reduction.Thus the standard emf of the cell is E0 = Eox0 + ERed0 = EZn/Zn2+0 + EMg2+/Mg0 = -(-0.76) + (-2.37) = -1.61 VFor a feasible cell, the cell potential should be positive. But here the value is negative indicating that cell is not a feasible one.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electric Potential and Potential Difference
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon