A student finds that the screw gauge that he is using to measure the thickness of a metal sheet has 50 divisions on the circular scale. If the pitch of the screw gauge is 0.05 cm, what is its least count?
0.01 mm
We know that, Count = (Pitch)(No. of divisions of the head scale)
= (0.05cm)(50) = 0.001 cm = 0.01 mm