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Question

A student focussed the image of a candle flame on a white screen using a lens. He noted down the position of the candle screen and the lens as mentioned below:
Position of candle = 12.0 cm
Position of lens = 50.0 cm
Position of the screen = 88.0 cm

(iv) Nature of image if he shift the candle between 12 cm and 31 cm?

A
Inverted, Real, Diminished
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B
Inverted, Real, Enlarged
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C
Erect, Virtual, Diminished
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D
Erect, Virtual, Enlarged
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Solution

The correct option is D Erect, Virtual, Enlarged
When the object is between 12 cm and 31 cm, the object distance is in the range:
u(19 cm,0)
But, -19 cm is the focal length of the lens. So, the object is placed between the focus and the optic centre. This means that the image formed is enlarged, virtual and erect.


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