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Fundamental Principle of Counting

A student has...

Question

A student has $5$ pants and $8$ shirts. The number of ways in which he can wear the dress in different combinations is

A

^{8} P_{5}

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B

^{8} C_{5}

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C

8! \times 5!

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D

40

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Solution

The correct option is D $40$
No. of shirts $= 8$
No. of pants $= 5$
No. of ways he can wear his clothes $=$ No. of ways he can wear a shirt AND No. of ways to wear pant $= 8 \times 5 = 40$

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