CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A student has taken 6000 molecules of fructose 1, 6-bisphosphate and 2 molecules of aldolase into an enzyme reaction mixture to determine its activity. After 5 minutes, 50% substrate was found converted into products. Then, what is the TON of aldolase and the total number of trioses formed by the enzyme action at the end of 5 minutes?

A
300, 3000
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
300, 6000
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
600, 3000
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
30, 6000
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 300, 6000
Turnover number is equivalent to the number of substrate molecules converted to product in a given unit of time on a single enzyme molecule, when a enzyme is saturated by substrate. Aldolase converted one substrate molecule to one product molecule.
If the total number of product after 5 minutes is (3000*2) = 6000.
So, the TON = 3000/(5*2) = 300
The total number of trioses formed by the enzyme action at the end of 5 minutes is 6000 (as one aldolase converts fructose bis phosphate into 2 triose phosphate).

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Glycolysis
BIOLOGY
Watch in App
Join BYJU'S Learning Program
CrossIcon