Question

A student has to score $40\%$ marks for passing the examination. If he gets $178$ marks, he fails by $22$ marks, find the maximum marks.

Answer 1

STEP 1 : Assuming the given values in the form of $x$

Let the maximum marks in the examination be $x$, then

Passing marks in the examination i.e. $40\%=\frac{40x}{100}=\frac{4x}{10}$ $--\left(1\right)$

STEP 2 : Forming the required equation

Given that if he gets $178$ marks, he fails by $22$ marks, i.e.

Passing marks in the examination $=178+22=200$ $--\left(2\right)$

From equation $\left(1\right)$ and $\left(2\right)$

$\frac{4x}{10}=200$

STEP 3 : Finding the value of $x$

$\frac{4x}{10}=200$

Transposing $\frac{4}{10}$ to the R.H.S. we get

$x=\frac{200\times 10}{4}=500$

Hence, the maximum marks in the examination is $500.$