The maximum mark is 500.
The mark student Has got is 178
Needed 22 marks more for not failing in the examination
So the student getting pass mark is 178 + 22 = 200.
The Student Need only to get 40% of the total marks
So 178+22 is the pass mark( that is 40% of total marks)
40% mark is 200. Then LetLthe 100% mark be 'X'.
To find out maximum mark ,
=> 40% of 'X' = 100%*200.
=> X = (200*100%)/40%.
=> X = 500.
That is The Maximum Mark Is 500
(we can Crosscheck it. That is 500 × (40/100) Gives 200, that is the passmark) so the answer is perfectly Correct As per the Question.