wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A student is standing at a distance of 50 meters from the bus. As soon as the bus starts its motion with an acceleration of 1ms, the student starts running towards the bus with a uniform velocity u. Assuming the motion to be along a straight road, the minimum value of u, so that the student is able to catch the bus is

A
5 ms
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
8 ms
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
10 ms
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
12 ms
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 10 ms
Let, the student catches the bus after t sec. So, it will cover distance ut.

Similarly, distance travelled by the bus will be 12at2. Therefore, for the given condition
ut=50+12 at2=50+t22u=50t+t2(as a=1 ms2)....(1)

So, to find the minimum value of u, dudt=0,d(50t+t2)dt=050t2+12=0t2=100t=10 s

Then putting value of t in equation (1), we get u=10 ms

flag
Suggest Corrections
thumbs-up
1
similar_icon
Similar questions
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Applications of equations of motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon