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Question

A student is standing at a distance of 50 metres from a bus. As soon as the bus begins its motion (starts moving away from student) with an acceleration of 1 m s2, the student starts running towards the bus with a uniform velocity u. Assuming the motion to be along a straight road, the minimum value of u, so that the student is able to catch the bus is:

A
5 ms1
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B
8 ms1
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C
10 ms1
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D
12 ms1
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Solution

The correct option is C 10 ms1
50+x=ut .....(1)
and x=t22 ...(2)

From (1) and (2),
50+t22=utt22ut+100=0
For real roots, discriminant = 0
4u2400=0u=10 m/s

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