Question

A student measured $10.0$ milliliters of an $HCl$ solution into a beaker and titrated it with a standard $NaOH$ solution of $0.09$M. The initial $NaOH$ burette reading was $34.7$ milliliters while the final reading showed $49.2$ milliliters. Find the molarity of the $HCl$ solution?

• A. $0.13$
• B. $0.47$
• C. $0.52$
• D. $1.57$
• E. $2.43$

Answer 1

The correct option is A $0.13$

$M_1{V}_1=M_2{V}_2$
$M_1=$ the molarity of the $HCl$ solution
$V_1=10.0$ mL $=$ the volume of the $HCl$ solution
$M_2=$ $0.09$ M $=$ the molarity of the $NaOH$ solution
$V_2=49.2-34.7=14.5$ mL $=$ the volume of the $NaOH$ solution
$M_1\times 10.0=0.09\times 14.5$
$M_1=0.13$ M.