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Byju's Answer

Standard XII

Physics

Screw Gauge

A student mea...

Question

A student measured the diameter of a small steel ball using a screw gauge of least count $0.001$ cm. The main scale reading is $5$ mm and zero of circular scale division coincides with $25$ divisions above the reference level. If screw gauge has a zero error of $- 0.004$ cm, the correct diameter of the ball is?

0.053

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0.521

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0.529

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0.525

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Solution

The correct option is A $0.529$ cm
Least count $= 0.001 c m$
M& R $= 5 m m$ and $25$ divisions
error $= - 0.004 c m$
Observed reading $= 0.5 + 25 \times 0.001$
$= 0.5 + 0.025$
$= .525 c m$
Actual reading $= .525 + 0.004$
$= 0.529 c m$

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The correct option is A 0.529cmLeast count =0.001cmM& R =5mm and 25 divisionserror =−0.004cmObserved reading =0.5+25×0.001 =0.5+0.025 =.525cmActual reading =.525+0.004 =0.529cm

The correct option is A $0.529$ cm
Least count $= 0.001 c m$
M& R $= 5 m m$ and $25$ divisions
error $= - 0.004 c m$
Observed reading $= 0.5 + 25 \times 0.001$
$= 0.5 + 0.025$
$= .525 c m$
Actual reading $= .525 + 0.004$
$= 0.529 c m$