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Question

# A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it ?

A
A vermier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cm
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B
A screw gausge having 100 divisions in the circular scale and pitch as 1 mm
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C
A meter scale
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D
A screw gauge have 50 divisions in the circular scale and pitch as 1 mm
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Solution

## The correct option is A A vermier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cm If student measure 3.50 cm it means that there in an uncertianly of order 0.01 cm. L.C of V.C = 1 MSD−1 VSD =110[1−910]=1100 cm Hence, B is correct option.

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