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Question
A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90s, 91s, 95s and 92 s. If the minimum division in the measuring clock is 1 s, then the reported mean time should be:
A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90s, 91s, 95s and 92 s. If the minimum division in the measuring clock is 1 s, then the reported mean time should be:
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Solution
The correct option is D
T = T1+T2+T3+T44
△ = |T1−T||T2−T||T3−T||T4−T|4
= 1.5s≈2s(Since least count is 1s)⇒final answer is 92±2s
T = T1+T2+T3+T44
△ = |T1−T||T2−T||T3−T||T4−T|4
= 1.5s≈2s(Since least count is 1s)⇒final answer is 92±2s
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