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Question

A student multiplied a number by 35 instead of 53 .what is the percentage error in the question?

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Solution

Let the number be x.

Then, ideally he should have multiplied by x by 53 . Hence Correct result was x×53=5x3

By mistake he multiplied x by 35 . Hence the result with error =3x5

Then, error =5x33x5=16x15

Error % =(errortruevalue)×100 =[(1615)x(53)x]×100=64 %


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