A student performs an experiment for determination of g-4 -2 l-T2- The error in length 1 is - l and in time T is - T and n is number of times the reading is taken- The measurement of g is most accurate for-

The correct option is D Δ l = 1 mm ; Δ T = 0.1 sec; n=50Given g = 4 π^2 l/T^2 ∴Δ gg = Δ ll + 2 Δ TT We will get the most accurate result, when the number of ...

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Standard XII

Physics

Analytical Picture of Forced Oscillation

A student per...

Question

A student performs an experiment for determination of $g = \frac{4 π^{2} l}{T^{2}}$ The error in length $l$ is $Δ l$ and in time $T$ is $Δ T$ and $n$ is number of times the reading is taken. The measurement of $g$ is most accurate for:

Δ l = 5 m m; Δ T = 0.2 s e c; n = 10

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Δ l = 5 m m; Δ T = 0.2 s e c; n = 20

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Δ l = 5 m m; Δ T = 0.1 s e c; n = 10

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Δ l = 1 m m; Δ T = 0.1 s e c; n = 50

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Solution

The correct option is D $Δ l = 1 m m; Δ T = 0.1 s e c; n = 50$
Given Data:
Acceleration due to gravity, $g = \frac{4 π^{2} l}{T^{2}}$
$\frac{Δ g}{g} = \frac{Δ l}{l} + 2 \frac{Δ T}{T}$

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A student performs an experiment for determination of g=4π2lT2 The error in length l is Δl and in time T is ΔT and n is number of times the reading is taken. The measurement of g is most accurate for:

The correct option is D Δl=1 mm;ΔT=0.1 sec;n=50Given Data:Acceleration due to gravity, g=4π2lT2 Δgg=Δll+2ΔTT

A student performs an experiment for determination of $g = \frac{4 π^{2} l}{T^{2}}$ The error in length $l$ is $Δ l$ and in time $T$ is $Δ T$ and $n$ is number of times the reading is taken. The measurement of $g$ is most accurate for:

The correct option is D $Δ l = 1 m m; Δ T = 0.1 s e c; n = 50$
Given Data:
Acceleration due to gravity, $g = \frac{4 π^{2} l}{T^{2}}$
$\frac{Δ g}{g} = \frac{Δ l}{l} + 2 \frac{Δ T}{T}$