A student performs experiment with simple pendulum and measures time for 10 vibrations. If he measures a time for 100 vibrations, the relative error in measurements of time period will be reduced by

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A student performs experiment with simple pendulum and measures time for 10 vibrations . If he measures time for 100 vibrations , the relative error in measurements of time period will be reduced by

Q. In an experiment of simple pendulum, the time period measured was

50

s for

25

vibrations when the length of the simple pendulum was taken

100

cm. If the least count of stop watch is

0.1

s and that of meter scale is

0.1

cm. Calculate the maximum possible error in the measurement of value of

g

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g

at the place of experiment is

9.7720 m s^{- 2}

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A students performs an experiment to determine the acceleration due to gravity (g) at a place using a simple pendulum. The length of the pendulum is 60 cm and the total time for 30 oscillations is 100s. What is maximum percentage error for the measurement g ? Given, least count for time $= 0.1 s$ and least count for length $= 0.1 c m$ .

Q. In an experiment to determine acceleration due to gravity by simple pendulum, a student commits 1 % positive error in the measurement of length and 3% negative error in the measurement of time period. The percentage error in the value of g will be :

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100

oscillations of a simple pendulum four times. That data set

90 s, 91 s, 95 s

and

92 s

. If the minimum division in the measuring clock is

1 s,

then he reported time should be

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