A student puts down his signature in graphite pencil. If the mass of carbon in the signature is $10^{- 12} g$ . Calculate the number of atoms in the signature.

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Solution

12 g of C = 1 mole of carbon.

$10^{- 12}$ g of C = $\frac{1}{12} \times 10^{- 12}$ mole of carbon.

We know that 1 mole of carbon contains $6.023 \times 10^{23}$ atoms of carbon.

So, $0.083 \times 10^{- 12}$ mole of carbon = $6.023 \times 10^{23} \times 0.084 \times 10^{- 12} \Rightarrow 5.09 \times 10^{10}$ atoms.

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A student puts down his signature in graphite pencil. If the mass of carbon in the signature is 10−12 g. Calculate the number of atoms in the signature.

12 g of C = 1 mole of carbon. 10−12 g of C = 112×10−12 mole of carbon. We know that 1 mole of carbon contains 6.023×1023 atoms of carbon. So, 0.083×10−12 mole of carbon = 6.023×1023×0.084×10−12⇒5.09×1010atoms.

A student puts down his signature in graphite pencil. If the mass of carbon in the signature is $10^{- 12} g$ . Calculate the number of atoms in the signature.