A student puts his signature with a graphite pencil. If the mass of carbon in the signature is $10^{12}$ g, calculate the number of carbon atoms in the signature.

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Solution

As we know that, in 1 mole or 12 g of carbon we have 6.022 x number of atoms in it.

Then, the number of atoms in g of carbon will be = $fraction numerator 6.022 cross times 10 to the power of 23 over denominator 12 end fraction$ $\times$ g = 5.02 $\times$

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A student puts his signature with a graphite pencil. If the mass of carbon in the signature is 1012 g, calculate the number of carbon atoms in the signature.

As we know that, in 1 mole or 12 g of carbon we have 6.022 x number of atoms in it. Then, the number of atoms in g of carbon will be = × g = 5.02 ×

A student puts his signature with a graphite pencil. If the mass of carbon in the signature is $10^{12}$ g, calculate the number of carbon atoms in the signature.

As we know that, in 1 mole or 12 g of carbon we have 6.022 x number of atoms in it.

Then, the number of atoms in g of carbon will be = $fraction numerator 6.022 cross times 10 to the power of 23 over denominator 12 end fraction$ $\times$ g = 5.02 $\times$