A student reads a barometer in the laboratory and finds the prevailing atmospheric pressure to be 720.0 mmHg. Which of the following is the correct option/s?

0.947 atm

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95.99 kPa

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9.599 \times 10^{3}

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720 torr

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Solution

The correct options are
A 0.947 atm
B 95.99 kPa
D 720 torr
we know, 1 atm = 760 mmHg
So, $720.0 m m H g \frac{1 a t m}{760 m m H g}$ = 0.947 atm
Similarly, 1 atm = 760 mmHg = 101.325kPa
So, $720.0 m m H g \frac{101.325 k P a}{760 m m H g}$ = 95.99 kPa

$720.0 m m H g \frac{760 t o r r}{760 m m H g}$ = 720 torr

Similarly, $720.0 m m H g \frac{101, 325 P a}{760 m m H g}$ = $9.599 \times 10^{4}$ Pa

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