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Question

A student records ΔQ,ΔU,ΔW for a thermodynamic cycle ABCA. Certain entries are missing. Find correct entry in following options.
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A
WBC=70J
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B
ΔQCA=130J
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C
ΔUAB=190J
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D
ΔUCA=160J
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Solution

The correct options are
B ΔUCA=160J
C ΔQCA=130J
Using ΔQ=ΔU+ΔW
For AB; 150=ΔUAB+40ΔUAB=110J
For BC; 10=ΔWBC+50ΔWBC=40J
Also internal energy change over complete cycle must be zero.
Thus, 110+50+ΔUCA=0ΔUCA=160J
ΔWT=40+3040=30J
So, ΔQT=30J150+10+ΔQCA=30
Thus, ΔQCA=130J

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