A student's $9.0 V, 7.5 W$ portable radio was left on from $9 : 00 P . M .$ until $3 : 00 A . M .$ How much charge passed through the wires?

18000 C

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24000 C

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6000 C

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12000 C

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Solution

The correct option is A $18000 C$
As we know,
Power, $P = V \cdot I$
$I = \frac{P}{V}$
$\Rightarrow I = \frac{Q}{t} = \frac{P}{V}$
$\Rightarrow Q = \frac{P}{V} \times t = \frac{7.5}{9} \times 3600 \times 6$
$= 18000 C$
$[∵ t = 9 P M$ to $3 A M = 6 h r = 6 \times 3600 s]$

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