A student scored $3$ marks more than what he did in the previous examination in which he had scored $12$ . Another student scored $12$ marks more than he did in the previous examination in which he had scored $84$ . Who had shown more improvement?

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Solution

Using the formula:

Increase $% = (\frac{I n c r e a s e}{O r i g i n a l v a l u e} \times 100) %$

Percentage improvement in the first examination for the first student

$= \frac{3}{2} \times % = 25 %$

Percentage improvement in the first examination for the second student

$= \frac{12}{84} \times % = 14.29 %$

Thus, the first student had improved more.

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A student scored 3 marks more than what he did in the previous examination in which he had scored 12. Another student scored 12 marks more than he did in the previous examination in which he had scored 84. Who had shown more improvement?

Using the formula:Increase%=(IncreaseOriginalvalue×100)%Percentage improvement in the first examination for the first student=32×%=25%Percentage improvement in the first examination for the second student=1284×%=14.29%Thus, the first student had improved more.

A student scored $3$ marks more than what he did in the previous examination in which he had scored $12$ . Another student scored $12$ marks more than he did in the previous examination in which he had scored $84$ . Who had shown more improvement?