Question

A student took five papers in an examination, where the full marks were the same for each paper. His marks in these papers were in the proportion of $6:7:8:9:10$. In all papers together, the candidate obtained $60\%$ of the total marks. Then, the number of papers in which he got more than $50\%$ marks is.

• A. $1$
• B. $3$
• C. $4$
• D. $5$

Answer 1

The correct option is C $4$

Let the full marks in one paper is 100 each

Then total marks are $100\times 5=500$

Given : The marks in these papers were in $6:7:8:9:10$ proportion

Then, total of proportion $=6+7+8+9+10=40$

Given in all papers he got total of $60\%$ marks

Then, marks obtained in five papers $=\frac{60}{100}\times 500=300$

Then, the marks in 1st paper is $=\frac{6}{40}\times 300=45$%

The marks in 2nd paper $=\frac{7}{40}\times 300=52.5$%

The marks in 3rd paper $=\frac{8}{40}\times 300=60$%

The marks in 4th paper $=\frac{9}{40}\times 300=67.5$%

The marks in 5th paper $=\frac{10}{40}\times 300=75$%

Then he got more than $50\%$ marks in four papers.