A student took some lead nitrate compound in a boiling tube and heated it strongly. The gas/gases evolved on heating this compound is/are :
(1) NO₂
(2) NO₂+ CO₂
(3) NO₂ + O₂
(4) N₂+ O₂

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Solution

When lead nitrate is heated it splits into simpler substances,
$\underset{Colourless}{2 Pb ({NO}_{3})_{2}} \to \underset{Yellow ppt}{2 PbO} + \underset{Brown fumes}{4 {NO}_{2}} + O_{2}$
So, NO₂ and O₂ are liberated from the reaction.

Hence, the correct answer is option 3.

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