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Question

A student uses a lens of focal length -50 cm. What is the nature of the lens and its power?

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Solution

Dear Student

The first point to remember is the sign convention. The sign assigned to concave lens is negative.


Now in the given question , f = -50cm
= -(50/100)m
=-1/2m =-0.5 m
Power = 1/f
Hence power = -1/( 0.5) or -2D
= -2D is the required answer.

Regards

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