wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A student uses a lens of focal length -50 cm. What is the nature of the lens and its power?

Open in App
Solution

Dear Student

The first point to remember is the sign convention. The sign assigned to concave lens is negative.


Now in the given question , f = -50cm
= -(50/100)m
=-1/2m =-0.5 m
Power = 1/f
Hence power = -1/( 0.5) or -2D
= -2D is the required answer.

Regards

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Myopia
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon