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Question

A student using the same two resistors, ammeter, voltmeter and battery, sets up two circuits A and B connecting the two resistors first in series and then in parallel.



If the ammeter and voltmeter readings in the two cases be I1, I2 and V1, V2 respectively he is likely to observe that :
(1) I1 = I2 but V1 ≠ V2
(2) I1 < I2 but V1 = V2
(3) I1 > I2 but V1 = V2
(4) I1 = I2 and V1 = V2

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Solution

As the ammeter holds negligible resistance, hence the voltage drop across the resistance is equal to the voltage of the battery. As the battery used in both cases is the same, that's why voltmeter will measure the same value in both the circuits. i.e. V1=V2

In circuit A, both the resistances are connected in series and in circuit B, they are connected in parallel. As the net resistance in circuit A is more than the net resistance in circuit B, and as given the same power supply is used in both the circuits, so the current in circuit A will be less than the current in circuit B.

Hence, the correct answer is option 2.

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