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Question
A student very cautiously traces the path of a ray through a glass slab for different values of the angle of incidence (∠i). He then measures the corresponding values of the angle of refraction (∠r) and the angle of emergence (∠e) for every value of the angle of incidence. On analyzing the measurements of these angles, his conclusion would be:
A student very cautiously traces the path of a ray through a glass slab for different values of the angle of incidence (∠i). He then measures the corresponding values of the angle of refraction (∠r) and the angle of emergence (∠e) for every value of the angle of incidence. On analyzing the measurements of these angles, his conclusion would be:
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Solution
The correct option is B ∠i = ∠e > ∠r
As the incident ray and the emergent ray will be parallel to each other, the angles that they make with the normal, i.e., ∠i and ∠e will be equal to each other.
Since glass is optically denser than air, the light ray on refraction into the glass, bends towards the normal, and on refraction out of the glass, bends away from the normal. Thus, ∠i > ∠r and ∠e > ∠r. Thus, on combining all these conclusions, we get, ∠i = ∠e > ∠r.
As the incident ray and the emergent ray will be parallel to each other, the angles that they make with the normal, i.e., ∠i and ∠e will be equal to each other.
Since glass is optically denser than air, the light ray on refraction into the glass, bends towards the normal, and on refraction out of the glass, bends away from the normal. Thus, ∠i > ∠r and ∠e > ∠r. Thus, on combining all these conclusions, we get, ∠i = ∠e > ∠r.
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