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Question

A student was asked to simplify the following
75223÷323112411257×710+115×31321225212+31.6+53.254.8+19.6

His answer was 315 Find the percentage error in the answer.

A
10%
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B
20%
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C
25%
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D
30%
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Solution

The correct option is C 25%
Given exp =7583÷32332432
57710+65×1035247212+3016+50325048+1096
=773÷32325257710+65×20156474221+158+25162524+548

3÷[(343)×25]57710+65×56521+55165548

=3÷[53×25]57[710+65×216]+4816

=3÷2357[710+215]+3

=9257×71057×215+3

=92123+3=82=4

Percentage error =4315315×100%

=4165165×100%=45165×100%=25%

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