A student when asked to measure two exterior angles of ∆ABC observed that the exterior angles at A and B are of 103° and 74° respectively. Is this possible? Why or why not?

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Solution

$Here, Internal angle at A + External angle at A = 180 ° Internal angle at A + 103 ° = 180 ° Internal angle at A = 77 ° Internal angle at B + External angle at B = 180 ° Internal angle at B + 74 ° = 180 ° Internal angle at B = 106 ° Sum of internal angles at A and B = 77 ° + 106 ° = 183 ° It means that the s um of internal angle s at A and B is greater than 180 °, which cannot be possible .$

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