A student, while testing the solubility of potassium nitrate at 313k, found that the solubility is 62 in 100g of water. What masses of potassium nitrate would be needed to produce a saturated solution of potassium nitrate in 50g of water at 1313k?
It is given that the solubility is 62 in 100g of water. This means that 62g of potassium nitrate will dissolve in 100g of water. If we want 50g of water
KNO3. H2O
62g 100g
? 50g
?= 50x62/100 = 31g
So 31g of KNO3 will dissolve in 50g of water to give the solution at 313K