A student who secures 20% marks in an examination fails by 30 marks. Another student who secures 32% gets 42 marks more than those required to pass. The percentage of marks required to pass is:
Correct option is B. 25
Let the total number of marks be x units
Thus, 20% of x=20100×x=0.2x
Also, 32% of x=32100×x=0.32x units
Therefore, according to the question,
⇒0.2x+30=0.32x−42
⇒0.32x−0.2x=30+42
⇒0.12x=72
⇒x=720.12=600
Hence, Passing marks are =20100×600+30=150
Thus, Percentage of marks required to pass =150600×100=25%