A stuntman plans to run across a roof top and then horizontally off it to land on the roof of next building. The roof of the next building is $4.9$ metre below the first one and $6.2$ metre away from it. What should be his minimum roof top speed in m/s, so that he can successfully make the jump?

3.1

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4.0

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4.9

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6.2

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Solution

The correct option is D $6.2$

Time taken to cover the depth 4.9 m $= \sqrt{\frac{2 h}{g}} = \sqrt{\frac{2 \times 4.9}{9.8}} = 1$

Stuntman has to cover the horizontal distance of $6.2 m$ in $1 s e c$

Minimum velocity required $= \frac{6.2}{1} = 6.2 m / s$

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A stuntman plans to run across a roof top and then horizontally off it to land on the roof of next building. The roof of the next building is 4.9 metre below the first one and 6.2 metre away from it. What should be his minimum roof top speed in m/s, so that he can successfully make the jump?

The correct option is D 6.2 Time taken to cover the depth 4.9 m=√2hg=√2×4.99.8=1 Stuntman has to cover the horizontal distance of 6.2m in 1sec Minimum velocity required =6.21=6.2m/s

A stuntman plans to run across a roof top and then horizontally off it to land on the roof of next building. The roof of the next building is $4.9$ metre below the first one and $6.2$ metre away from it. What should be his minimum roof top speed in m/s, so that he can successfully make the jump?

The correct option is D $6.2$

Time taken to cover the depth 4.9 m $= \sqrt{\frac{2 h}{g}} = \sqrt{\frac{2 \times 4.9}{9.8}} = 1$

Stuntman has to cover the horizontal distance of $6.2 m$ in $1 s e c$

Minimum velocity required $= \frac{6.2}{1} = 6.2 m / s$