A submarine after travelling 100 km from the sea shore, descended 1 1/10 km below the below the sea level. Then it ascended about 3/5 km. The next day, it again descended by 9/10 km. What is its current position with the respect to the sea level? Whatnis the horizontal distance of the submarine from the sea shore?

In the answer section the answer to this question is given ' 7/5 km '

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Solution

First submarine decend by 11/10 km so current position is -11/10 km .

Now it assends by
3/5 km so now position is -11/10 + 3/5
= -1/2

Again it descends by 9/10 so now current position is -1/2 - 9/10

= -14/10 = -7/5
so i is at 7/5 km below sea level.

- sign indicates that it is below sea level.

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First submarine decend by 11/10 km so current position is -11/10 km . Now it assends by 3/5 km so now position is -11/10 + 3/5 = -1/2 Again it descends by 9/10 so now current position is -1/2 - 9/10 = -14/10 = -7/5 so i is at 7/5 km below sea level. - sign indicates that it is below sea level.

First submarine decend by 11/10 km so current position is -11/10 km .

Now it assends by
3/5 km so now position is -11/10 + 3/5
= -1/2

Again it descends by 9/10 so now current position is -1/2 - 9/10

= -14/10 = -7/5
so i is at 7/5 km below sea level.

- sign indicates that it is below sea level.