A submarine was situated 800 feet below sea level. If it descends 250 per hour, what is its new position after 6 hours ?

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Solution

$The original level of the submarine below the sea level is 800 feet . As, the submarine descends 250 feet per hour . The depth it descends in 6 hours = (6 \times 250) feet = 1500 feet . Therefore, the new position of the submarine after 6 hours = (800 + 1500) feet = 2300 feet .$

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A submarine was situated 800 feet below sea level. If it descends 250 per hour, what is its new position after 6 hours ?

The original level of the submarine below the sea level is 800 feet.As, the submarine descends 250 feet per hour.The depth it descends in 6 hours=6×250 feet=1500 feet.Therefore, the new position of the submarine after 6 hours=800+1500 feet=2300 feet.

$The original level of the submarine below the sea level is 800 feet . As, the submarine descends 250 feet per hour . The depth it descends in 6 hours = (6 \times 250) feet = 1500 feet . Therefore, the new position of the submarine after 6 hours = (800 + 1500) feet = 2300 feet .$