Question

A substance A decomposes by a first order reaction starting initially with [A]= 2 M and after 200 min [A]=0.15 M. for this reaction what is the value of k

Answer 1

Dear Student,

​$$\begin{gathered} \mathrm{k}=\frac{2.303}{\mathrm{t}}\log \frac{\mathrm{a}}{\mathrm{a}-\mathrm{x}} \\ =\frac{2.303}{200}\log \frac{2.00}{0.15} \\ =\frac{2.303}{200}\log 13.33 \\ =0.0129{\min }^{-1} \end{gathered}$$