Question

A substance is completely trimerized on dissolution in a solvent. The Van't Hoff factor ($i$) for such change is:

• A. $1$
• B. $2$
• C. $3$
• D. $1/3$

Answer 1

The correct option is C $3$

Given that,

$\alpha =1$.

Now,

$3A⟶A_3$

1 0

$1-\alpha$ $\frac{\alpha }{3}$

Van't Hoff Factor $\left(i\right)=1-\alpha +\frac{\alpha }{3}=1-1+\frac{1}{3}=\frac{1}{3}$